Exercice Corrige Electrocinetique 〈2025-2026〉

[ \boxedV_C(t) = E \left(1 - e^-t/\tau\right) \quad \textfor \quad 0 \leq t \leq t_1 ] where ( \tau = RC ). 2.2 Calcul de la constante de temps (Time constant) [ \tau = R \cdot C = (1 \times 10^3) \cdot (100 \times 10^-6) = 10^3 \cdot 10^-4 = 0.1 \ \texts ]

With ( i(t) = C \fracdV_Cdt ), we get:

[ \boxed\tau = 100 \ \textms ] At ( t_1 = 0.5 \ \texts ): exercice corrige electrocinetique

[ RC \fracdV_Cdt + V_C = E ]

[ 0 = R i + V_C \quad \Rightarrow \quad RC \fracdV_Cdt + V_C = 0 ] [ \boxedV_C(t) = E \left(1 - e^-t/\tau\right) \quad

Solution: