Calcolo Combinatorio E Probabilita -italian Edi... May 2026

"But wait!" Luca interrupted. "What if you also require that the three chosen customers are all from different towns, and there are 4 towns with 5 customers each? And the selection without replacement must include one from each town — then what's the probability that a random ordered selection of 3 customers satisfies that?"

"So," Chiara said, "a 1% chance. Rare, but possible." Calcolo combinatorio e probabilita -Italian Edi...

Total cards: 40. Cards with value 1: 4 (one per suit). [ P(\text{not drawing a '1'}) = \frac{36}{40} = \frac{9}{10} ] "But wait

Enzo nodded. "It happened once. A trio of truffle enthusiasts. The pizza was… intense." A burly farmer named Marco asked, "What about the chance that all three toppings are different?" Rare, but possible

Total possible ordered selections (without replacement from 20): (20 \times 19 \times 18 = 6840).

Thus, overall probability that a pizza is made the customers are from three different towns: [ \frac{9}{10} \times \frac{25}{57} = \frac{225}{570} = \frac{45}{114} = \frac{15}{38} \approx 0.3947 ] The Revelation Chiara finished her wine. "Enzo, your pizza game is a lesson in combinatorics and probability."

Enzo clapped. "A combinatorial probability with two stages!"